Jump to content

Terminal Velocity of Giant Drop


Recommended Posts

This probably explains it better than me. http://en.wikipedia.org/wiki/Terminal_velocity As you can see, its a pretty complex thing to work out. But basically, if there was no air friction things would keep accelerating at 9.8 ms^-2 until they hit the ground. But in reality air friction causes drag, and the faster you are moving the more drag occurs. When it is falling fast enough the upward drag forces will equal the downward weight force of the object, and since the net force on it is zero it stops accelerating, and just keeps falling at a constant rate instead.

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.


  • Recently Browsing   0 members

    • No registered users viewing this page.
  • Create New...

Important Information

By using this site, you agree to our Terms of Use. We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.